Factorial Program In Vbscript Using For Loop

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Function returns a factorial of a number (e.g., 6!). Perhaps the easiest illustration of recursion available for beginners Instructions: Copy the declarations and code below and paste directly into your VB project.

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Write a vb script to calculate factorial of a number? Module Factorial_ForLoop Sub main Dim n, i, f As Integer Console. Write ('Enter a Number: ') n = CInt (Console. ReadLine ()) f = 1 If n.

Output: seq 6 0815 fac.0 1 2 6 18 78 2d0 [ ] For maximum compatibility, this program uses only the basic instruction set. Works with: version Any - tested with release INT g = 7; [ ] REAL p = [ ] REAL ( 0.9980993, 6218851, -12224028, 77765313, -16214059, 78686905, -0.6572012, 9.195716e-6, 1.493116e-7 ) [ @0 ]; PROC complex gamma = ( COMPL in z ) COMPL: ( # Reflection formula # COMPL z:= in z; IF re OF z. Output: [ ] Iterative [ ] print 'enter a number, n = '; input n print string(n) + '! = ' + string(factorial(n)) function factorial(n) factorial = 1 if n > 0 then for p = 1 to n factorial *= p next p end if end function Recursive [ ] print 'enter a number, n = '; input n print string(n) + '! = ' + string(factorial(n)) function factorial(n) if n > 0 then factorial = n * factorial(n-1) else factorial = 1 end if end function [ ] @ off /p x= /a fs=% x%-1 y=% x% /L%% a (% fs%, -1, 1 ) /a y*=%% a% x% 0 y=1% y% [ ]. > factorial 8;; val it: int = 40320 > factorial 800I;; val it: bigint = 0000000I [ ].

Library: provides the following iterative procedure which can be included with 'link factors': procedure factorial (n ) #: return n! (n factorial) local i n:= integer (n ) runerr ( 101, n ) if n. Output: 728000 [ ] PROC FACTORIAL(ARG) U; BEGIN ITEM ARG U; ITEM TEMP U; TEMP = 1; FOR I:2 BY 1 WHILE I. Works with: version 0.6 Built-in version: help?> factorial search: factorial Factorization factorize factorial(n) Factorial of n.

If n is an Integer, the factorial is computed as an integer (promoted to at least 64 bits). Note that this may overflow if n is not small, but you can use factorial(big(n)) to compute the result exactly in arbitrary precision. If n is not an Integer, factorial(n) is equivalent to gamma(n+1).

Julia> factorial(6) 720 julia> factorial(21) ERROR: OverflowError() [.] julia> factorial(21.0) 5.70944e19 julia> factorial(big(21)) Dynamic version: function fact(n::Integer) n ', fact(i)) end. Output: Input a number: 49 49! = 000 (using iteration) 49!

= 000 (using recursion) [ ] > ( (factorial n ) ( ( ( + n 1 ) ) ) ) ( (n ) ( ( ( + n 1 ) ) ) ) > (factorial 4 ) 24 [ ] (from Nial help file) fact is recur [ 0 =, 1 first, pass, product, -1 +] Using it fact 4 =24 [ ] Library [ ] import math let i:int = fac(x) Recursive [ ] proc factorial(x): int = if x > 0: x * factorial(x - 1) else: 1 Iterative [ ] proc factorial(x: int): int = result = 1 for i in 2.x: result *= i [ ] Recursive [ ] [ dup 1 > [ dup 1 - factorial * ] when ] 'factorial; ( test ) 4 factorial. ( => 24 ) 10 factorial. ( => 3628800 ) [ ]. Works with: MODULE Factorial; IMPORT Out; VAR i: INTEGER; PROCEDURE Iterative (n: LONGINT ): LONGINT; VAR i, r: LONGINT; BEGIN ASSERT (n > = 0 ); r:= 1; FOR i:= n TO 2 BY - 1 DO r:= r * i END; RETURN r END Iterative; PROCEDURE Recursive (n: LONGINT ): LONGINT; VAR r: LONGINT; BEGIN ASSERT (n > = 0 ); r:= 1; IF n > 1 THEN r:= n * Recursive (n - 1 ) END; RETURN r END Recursive; BEGIN FOR i:= 0 TO 9 DO Out. String ( 'Iterative ' );Out. Int (i, 0 );Out. Int (Iterative (i ), 0 );Out.